1/3y^2-5/3y-8=0

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Solution for 1/3y^2-5/3y-8=0 equation: 


y in (-oo:+oo)

(1/3)*y^2-((5/3)*y)-8 = 0

(1/3)*y^2+(-5/3)*y-8 = 0

1/3*y^2-5/3*y-8 = 0

DELTA = (-5/3)^2-(-8*1/3*4)

DELTA = 121/9

DELTA > 0

y = ((121/9)^(1/2)+5/3)/(1/3*2) or y = (5/3-(121/9)^(1/2))/(1/3*2)

y = 8 or y = -3

y in { -3, 8 }

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